## Trigonometry (11th Edition) Clone

$sin (45^{\circ}) = \frac{1}{\sqrt{2}}$
Let's consider a triangle with angles $45^{\circ}, 45^{\circ},$ and $90^{\circ}$ that has sides of length $1, 1,$ and $\sqrt{2}$. Let $x = 1, y= 1$, and $r = \sqrt{2}$. Then: $sin(45^{\circ}) = \frac{y}{r} = \frac{1}{\sqrt{2}}$