Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises - Page 54: 24


$\cot$ 73$^{\circ}$ = $\tan$ 17$^{\circ}$

Work Step by Step

According to the Cofunction Identities $\cot$ $A$ = $\tan$ (90$^{\circ}$ - $A$) Therefore: $\cot$ 73$^{\circ}$ = $\tan$ (90$^{\circ}$ - 73$^{\circ}$) = $\tan$ 17$^{\circ}$ Therefore: $\cot$ 73$^{\circ}$ = $\tan$ 17$^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.