## Trigonometry (11th Edition) Clone

$p=q=7$
Similar triangles have corresponding sides in proportion. Side of length 16 corresponds to side of length 7 and side of length 16 corresponds to side of length p. This leads to the following proportion: $\frac{16}{7}=\frac{16}{p}$ Solving, $16\times7=16\times p$ $112=16p$ Dividing both sides by $16, $$p=7. Side of length 16 corresponds to side of length 7 and side of length 16 corresponds to side of length q. This leads to the following proportion: \frac{16}{7}=\frac{16}{q} Solving, 16\times7=16\times q 112=16q Dividing both sides by 16,$$q=7$.