Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 1 - Review Exercises - Page 43: 15


0.25 km

Work Step by Step

1. Corresponding sides of familiar triangles are proportional $\frac{PQ}{BA}=\frac{PC}{AC}$ 2. Substitute the values solve for BA: $\frac{1.25mm}{BA}=\frac{150km}{30km}$ $BA=\frac{1.25\times 30}{150}=0.25km$
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