#### Answer

Graph "I" is the correct sketching.

#### Work Step by Step

For $y = (x+2)^2 - 1,$
when $x=−2, y=-1$
The curve passes through $(−2,-1)$
Since the graph of $y=(x+2)^2-1$ is the same as the graph of $y=x^2$ but at a horizontal translation of 2 units to the left and a vertical translation of 1 unit down, graph "I" is the correct sketching.