## Trigonometry (11th Edition) Clone

For $y = (x+2)^2 - 1,$ when $x=−2, y=-1$ The curve passes through $(−2,-1)$ Since the graph of $y=(x+2)^2-1$ is the same as the graph of $y=x^2$ but at a horizontal translation of 2 units to the left and a vertical translation of 1 unit down, graph "I" is the correct sketching.