## Trigonometry (11th Edition) Clone

For $y=-x^2,$ when $x=0, y=0$ and $x=1, y=-1$ The curve passes through $(0,0)$ and $(1,-1)$ Since the graph of $y=-x^2$ is the same as the graph of $y=x^2$ across the x-axis, graph "D" is the correct sketching.