Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Appendix B - Graphs of Equations - Exercises - Page 427: 46

Answer

a) The center-radius form of the circle equation is $(x + \sqrt{3})^2$ + $(y + \sqrt{3})^2$ = $3$ b) Refer to Graph I for the graphing.

Work Step by Step

Center of the circle = $(-\sqrt{3}, -\sqrt{3})$ and Radius r = $\sqrt{3}$ a) The center-radius form of the circle equation is $(x – (-\sqrt{3}))^2$ + $(y – (-\sqrt{3}))^2$ = $(\sqrt{3})^2$ $(x + \sqrt{3})^2$ + $(y + \sqrt{3})^2$ = $3$ b) Refer to Graph I for the graphing.
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