Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Appendix B - Graphs of Equations - Exercises - Page 427: 44

Answer

a) The center-radius form of the circle equation is $(x + 3)^2$ + $(y + 2)^2$ = $36$ b) Refer to Graph I for the graphing.
1497963620

Work Step by Step

Center of the circle = (-3, -2) and Radius r = 6 a) The center-radius form of the circle equation is $(x – (-3))^2$ + $(y – (-2))^2$ = $6^2$ $(x + 3)^2$ + $(y + 2)^2$ = $36$ b) Refer to Graph I for the graphing.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.