Stats Modeling the World, 4th Edition

Published by Pearson
ISBN 10: 0133151549
ISBN 13: 978-0-13315-154-1

Chapter 5 - The Standard Deviation as a Ruler and the Normal Model - Exercises - Page 132: 15

Answer

a) Megan b) Anna

Work Step by Step

a) Anna: $\frac{83+83}{2}=83\lt85$ Megan: $\frac{77+95}{2}=86\gt85$ So Megan qualifies. b) French: Anna: $z=\frac{y-\mu}{\rho}=\frac{83-81}{5}=0.4$ Megan: $z=\frac{y-\mu}{\rho}=\frac{77-81}{5}=-0.8$ Spanish: Anna: $z=\frac{y-\mu}{\rho}=\frac{83-74}{15}=0.6$ Megan: $z=\frac{y-\mu}{\rho}=\frac{95-74}{15}=1.4$ Total: Anna: $0.4+0.6=1.0$ Megan: $-0.8+1.4=0.6$ Anna qualifies.
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