Chapter 9 - Section 9.2 - Assess Your Understanding - Applying the Concepts - Page 452: 50g

Lower Bound = 46.29, Upper Bound = 52.71 The confidence interval has increased due to the outlier.

Here we have n = 36, df = n-1 = 35, x̅ = 49.5 and s = 9.491 Confidence = 95% α = 1 - 0.95 = 0.05, α/2 = 0.025, $t_{α/2} = 2.03$ $E = 2.03 \times \frac{9.491}{\sqrt 36} = 3.21 $ $ Lower Bound = x̅ - E = 49.5 - 3.21 = 46.29$ $Upper Bound = x̅ + E = 49.5 + 3.21 = 52.71$