Answer
$P(Excellent~|~C)=\frac{13}{30}\approx0.433$
Work Step by Step
$N(C)=6+11+13=30$ and $N(C~and~Excellent)=13$. Using the Conditional Rule (page 288):
$P(Excellent~|~C)=\frac{N(C~and~Excellent)}{N(C)}=\frac{13}{30}\approx0.433$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 5 - Section 5.4 - Consumer Reports - His 'N' Hers Razors? - Page 296: d
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