Answer
$P(Poor)=\frac{7}{90}\approx0.078$
Work Step by Step
$N(A)=1+8+21=30$.
$N(B)=0+11+19=30$.
$N(C)=6+11+13=30$.
$Total=N(A)+N(B)+N(C)=90$.
$N(Poor)=1+0+6=7$.
$P(Poor)=\frac{N(Poor)}{Total}=\frac{7}{90}\approx0.078$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 5 - Section 5.4 - Consumer Reports - His 'N' Hers Razors? - Page 296: b
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