Answer
$P(E~|~F)=\frac{76}{185}\approx0.411$
Work Step by Step
$N(E~and~F)=380$ and $N(E)=925$.
Using the Conditional Probability Rule (see page 288):
$P(E~|~F)=\frac{N(E~and~F)}{N(E)}=\frac{380}{925}=\frac{76}{185}\approx0.411$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 5 - Section 5.4 - Assess Your Understanding - Vocabulary and Skill Building - Page 292: 6
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