Answer
$P(F~|~E)=\frac{21}{37}\approx0.568$
Work Step by Step
$N(E~and~F)=420$ and $N(E)=740$.
Using the Conditional Probability Rule (see page 288):
$P(F~|~E)=\frac{N(E~and~F)}{N(E)}=\frac{420}{740}=\frac{21}{37}\approx0.568$
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