Answer
No, there is no day in which a fatality is more likely to be male.
Work Step by Step
N(Sunday) = 12,547 and N(male and Sunday) = 8,222
N(Monday) = 9,154 and N(male and Monday) = 6,046
N(Tuesday) = 8,792 and N(male and Tuesday) = 5,716
N(Wednesday) = 8,793 and N(male and Wednesday) = 5,782
N(Thursday) = 9,617 and N(male and Thursday) = 6,315
N(Friday) = 12,045 and N(male and Friday) = 7,932
N(Saturday) = 14,382 and N(male and Saturday) = 9,558
Using the Conditional Probability Rule (see page 288):
$P(male~|~Sunday)=\frac{N(male~and~Sunday)}{N(Sunday)}=\frac{8,222}{12,547}\approx0.655$
$P(male~|~Monday)=\frac{N(male~and~Monday)}{N(Monday)}=\frac{6,046}{9,154}\approx0.660$
$P(male~|~Tuesday)=\frac{N(male~and~Tuesday)}{N(Tuesday)}=\frac{5,716}{8,792}\approx0.650$
$P(male~|~Wednesday)=\frac{N(male~and~Wednesday)}{N(Wednesday)}=\frac{5,782}{8,793}\approx0.658$
$P(male~|~Thursday)=\frac{N(male~and~Thursday)}{N(Thursday)}=\frac{6,315}{9,617}\approx0.657$
$P(male~|~Friday)=\frac{N(male~and~Friday)}{N(Friday)}=\frac{7,932}{12,045}\approx0.659$
$P(male~|~Saturday)=\frac{N(male~and~Saturday)}{N(Saturday)}=\frac{9,558}{14,382}\approx0.665$
