Chapter 5 - Section 5.4 - Assess Your Understanding - Applying the Concepts - Page 293: 16

$P(100,000~dollars~per~year~or~more~|~Northeast)=\frac{0.054}{0.179}\approx0.302$

$P(Northeast)=17.9$% $=0.179$ $P(100,000~dollars~per~year~or~more~and~Northeast) = 5.4$% $=0.054$ Using the Conditional Probability Rule (see page 288): $P(100,000~dollars~per~year~or~more~|~Northeast)=$ $=\frac{P(100,000~dollars~per~year~or~more~and~Northeast)}{P(Northeast)}=\frac{0.054}{0.179}\approx0.302$