Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Section 5.2 - Assess Your Understanding - Vocabulary and Skill Building - Page 276: 22

Answer

$P(\text{Maxfli or Top-Flite})=0.55$

Work Step by Step

$N(Titleist)=9$, $N(Maxfli)=8$ and $N(Top-Flite)=3$ Let S be the sample space. $N(S)=N(Titleist)+N(Maxfli)+N(Top-Flite)=9+8+3=20$ $P(Maxfli)=\frac{N(Maxfli)}{N(S)}=\frac{8}{20}=0.40$ $P(Top-Flite)=\frac{N(Top-Flite)}{N(S)}=\frac{3}{20}=0.15$ The events "Titleist" and "Maxfli" are mutually exclusive, so: $P(\text{Maxfli or Top-Flite})=P(Maxfli)+P(Top-Flite)=0.40+0.15=0.55$
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