Answer
$P(E and F)=0$
Work Step by Step
$P(E)=0.25$, $P(F)=0.45$ and, according to problem 15, $P(E or F)=0.7$
If E and F are mutually exclusive:
$P(E or F)=P(E)+P(F)-P(E and F)$
$0.7=0.25+0.45-P(E and F)$
$P(E and F)=0.7-0.7=0$
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