Answer
P(male or Sunday) $=\frac{26,948}{37,665}\approx0.715$
Work Step by Step
The sample space: 75,330 drivers involved in fatal crashes in the United States in 2009. So, N(S) = 75,330.
According to the marginal distribution (see definition, page 235) of the first column: N(male) = 49,571.
According to the marginal distribution (see definition, page 235) of the first row: N(Sunday) = 12,547.
According to the cell in the first row, first column: N(male and Sunday) = 8,222.
P(male or Sunday) = P(male) + P(Sunday) - P(male and Sunday) =
$\frac{N(male)}{N(S)}+\frac{N(Sunday)}{N(S)}-\frac{N(\text{male and Sunday})}{N(S)}=\frac{49,571}{75,330}+\frac{12,547}{75,330}-\frac{8,222}{75,330}=\frac{53,896}{75,330}=\frac{26,948}{37,665}\approx0.715$
