Answer
P(female or 1 ticket) $=\frac{122}{197}\approx0.619$
Work Step by Step
The sample space: 197 individuals. So, N(S) = 197.
According to the marginal distribution (see definition, page 235) of the first row: N(female) = 115.
According to the marginal distribution (see definition, page 235) of the second column: N(1 ticket) = 21.
According to the cell in the first row, second column: N(female and 1 ticket) = 14.
P(female or 1 ticket) = P(female) + P(1 ticket) - P(female and 1 ticket) =
$\frac{N(female)}{N(S)}+\frac{N(1 ticket)}{N(S)}-\frac{N(\text{female and 1 ticket})}{N(S)}=\frac{115}{197}+\frac{21}{197}-\frac{14}{197}=\frac{122}{197}\approx0.619$
