Answer
$Σresidual^2=3$
(Other answers are possible depending on the initial points chosen.)
Work Step by Step
Since $ŷ =2x+1$
$Σresidual^2=Σ(y_i-ŷ _i)^2=Σ[y_i-(2x_i+1)]^2=Σ(y_i-2x_i-1)^2$
$Σresidual^2=(-4-2\times(-2)-1)^2+(0-2\times(-1)-1)^2+(1-2\times0-1)^2+(4-2\times1-1)^2+(5-2\times2-1)^2$
$Σresidual^2=3$