Answer
$Σresidual^2=1.6$
Work Step by Step
Since $ŷ =1.1x−3.7$
$Σresidual^2=Σ(y_i-ŷ _i)^2=Σ[y_i-(1.1x−3.7)]^2=Σ(y_i-1.1x_i+3.7)^2$
$Σresidual^2=(0-1.1\times3+3.7)^2+(2-1.1\times5+3.7)^2+(3-1.1\times7+3.7)^2+(6-1.1\times9+3.7)^2+(9-1.1\times11+3.7)^2$
$Σresidual^2=1.6$