Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 3 - Section 3.3 - Assess Your Understanding - Applying the Concepts - Page 163: 6a

Answer

$μ=520.2$ $σ=117.3$

Work Step by Step

$x_1=$ First Class Midpoint = 250 $x_2=$ Second Class Midpoint = 350 $x_3=$ Third Class Midpoint = 450 $x_4=$ Fourth Class Midpoint = 550 $x_5=$ Fifth Class Midpoint = 650 $x_6=$ Sixth Class Midpoint = 750 $μ=\frac{Σx_if_i}{Σf_i}=\frac{250\times36305+350\times193968+450\times459010+550\times467855+650\times286518+750\times104334}{1548020}=520.2$ $σ=\sqrt {\frac{Σ(x_i-μ)^2f_i}{Σf_i}}=\sqrt {\frac{(250-520.2)^2\times36305+(350-520.2)^2\times193968+(450-520.2)^2\times459010+(550-520.2)^2\times467855+(650-520.2)^2\times286518+(750-520.2)^2\times104334}{1548020}}=117.3$
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