Answer
$H=5.157$
Work Step by Step
$H=\frac{12}{N(N+1)}[\frac{R_1^2}{n_1}+\frac{R_2^2}{n_2}+\frac{R_3^2}{n_3}+\frac{R_4^2}{n_4}]-3(N+1)=\frac{12}{40(40+1)}[\frac{149^2}{10}+\frac{207^2}{10}+\frac{267^2}{10}+\frac{197^2}{10}]-3(40+1)=5.157$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 15 - Section 15.7 - Assess Your Understanding - Applying the Concepts - Page 781: 4b
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