Answer
$H=18.77$
Work Step by Step
$H=\frac{12}{N(N+1)}[\frac{R_1^2}{n_1}+\frac{R_2^2}{n_2}+\frac{R_3^2}{n_3}+\frac{R_4^2}{n_4}+\frac{R_5^2}{n_5}]-3(N+1)=\frac{12}{40(40+1)}[\frac{48^2}{8}+\frac{226^2}{8}+\frac{144^2}{8}+\frac{194.5^2}{8}+\frac{207.5^2}{8}]-3(40+1)=18.77$
