Answer
$R^2=0.8331=83.31$%
83.31% of the variation of the course grade is explained by the model found in part (b).
$R^2_{adj}=0.7854=78.54$%
It adjusts the value of $R^2$, given the size of the sample, n, and the number of explanatory variables, k.
Work Step by Step
See the results in MINITAB, part (b).
$R^2=0.8331=83.31$%
$R^2_{adj}=1-(\frac{n-1}{n-k-1})(1-R^2)=1-(\frac{10-1}{10-2-1})(1-0.8331)=0.7854$
