Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 14 - Review - Review Exercises - Page 729: 2a

Answer

$β_0=3.859$ $β_1=-0.1049$ $Expected~GPA=3.3345$

Work Step by Step

In MINITAB, enter the Row Chosen values in C1 and in C2 enter the GPA values. Select Stats -> Regression -> Regression -> Fit Regression Model$b_0=3.859$ and $b_1=-0.1049$ Enter C2 in "Responses" and C1 in "Continuous Predictors" The least-squares regression line ($ŷ =b_1x+b_0$) will be shown in "Regression Equation", where C2 is ŷ (GPA) and C1 is x (Row Chosen) $ŷ =-0.1049x+3.859$ That is: $b_0=3.859$ and $b_1=-0.1049$ $b_0$ is the estimate for $β_0$ and $b_1$ is the estimate for $β_1$. For the fifth row, that is, $x=5$: $ŷ =-0.1049\times5+3.859=3.3345$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.