Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.1 - 5.19 - Learning the Mechanics: 5.6a

Answer

3

Work Step by Step

$P(x \geq a) = 0.5$ $P(x \geq a) = ∫_{a}^{∞} f(x).dx$ = $∫_{a}^{∞} \frac{1}{d-c}.dx$ = $∫_{a}^{∞} \frac{1}{2}.dx$ = $∫_{a}^{4} \frac{1}{2}.dx + $∫_{4}^{∞} \frac{1}{2}.dx$ = 1/2 (4-a) + 1/2 (0)= (4-a)/2 Since $P(x \geq a) = 0.5$ (4-a)/2 = 0.5 4-a = 1 a = 3
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.