Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.1 - 5.19 - Applying the Concepts - Basic: 5.9b

Answer

0.25

Work Step by Step

$P(2 \leq x \leq 2.5) = ∫_{2}^{2.5} f(x).dx$ = $∫_{2}^{2.5} \frac{1}{d-c}.dx$ = $∫_{2}^{2.5} \frac{1}{2}.dx$ = 1/22 (2.5-2) = 0.5/2 = 0.25
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