## Statistics (12th Edition)

f(x) = 1/d-c = 1/3-1 = 1/2 $P(1 \leq x \leq 3) = ∫_{1}^{3} x.f(x).dx$ = $∫_{1}^{3} \frac{1}{d-c}.x.dx$ = $∫_{1}^{3} \frac{1}{2}x..dx$ = $1/2 [x^{2}/2]_{1}^{3}$ = 1/2. [9/2 - 1/2 = 1/2. [8/2] = 2