Answer
$10$
Work Step by Step
The number of ways of selecting $n$ elements from $N$ elements is given by the combinations rule:
$$\binom{N}{n} = \dfrac{N!}{n! (N-n)!}$$
The number of ways of selecting 2 elements from 5 elements is given by
$$\binom{5}{2}$$
${\displaystyle{\binom{5}{2}} = \dfrac{5!}{2! \, (5-2)!} = \dfrac{5!}{2! \, 3!} = \dfrac{5 \cdot 4 \cdot 3 \cdot 2 \cdot 1}{(2 \cdot 1)(3 \cdot 2 \cdot 1)}}$
${\displaystyle{\binom{5}{2}} = \dfrac{5 \cdot 4 \cdot 3 \cdot 2 \cdot 1}{(2 \cdot 1)(3 \cdot 2 \cdot 1)} = \dfrac{5 \cdot 4}{2 \cdot 1} = \dfrac{20}{2} = \boxed{10}}$
