Introductory Statistics 9th Edition

Published by Wiley
ISBN 10: 1-11905-571-7
ISBN 13: 978-1-11905-571-6

Chapter 7 - Section 7.1 - Sampling Distribution, Sampling Error, and Nonsampling Errors - Exercises - Page 280: 7.4

Answer

The table shows the calculations required for the computation of the mean and standard deviation. Hence, we can verify that the mean and standard deviation for the population probability distribution are 80.60 and 8.09 respectively. $μ=∑xP(x) $= 80.6 σ=$\sqrt ∑(x^2P(x)- μ^2)$ = $\sqrt 6561.8-(80.6)^2 $ = 8.09
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Work Step by Step

The table shows the calculations required for the computation of the mean and standard deviation. Hence, we can verify that the mean and standard deviation for the population probability distribution are 80.60 and 8.09 respectively. $μ=∑xP(x) $= 80.6 σ=$\sqrt ∑(x^2P(x)- μ^2)$ = $\sqrt 6561.8-(80.6)^2 $ = 8.09
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