#### Answer

The table shows the calculations required for the computation of the mean and standard deviation. Hence, we can verify that the mean and standard deviation for the population probability distribution are 80.60 and 8.09 respectively.
$μ=∑xP(x) $= 80.6
σ=$\sqrt ∑(x^2P(x)- μ^2)$ = $\sqrt 6561.8-(80.6)^2 $ = 8.09