Answer
Mean =μ = $∑xP(x)$ = 2.5546 units of defective tires
Thus, it is expected that 2.5546 units of defective tires are on this fleet of limos, with a standard deviation of 1.3155 units of defective tires.
Standard Deviation
= $\sqrt∑x^{2}P(x) -μ^{2}$
= $\sqrt 8.2564-2.5546^{2}$
=1.3155 units of defective tires
If k = 2, at least 75% of the number of defective tires on a limo lie between $μ-2σ$ and $μ+2σ$.
μ =2.5546, σ = 1.3155
$μ-2σ$ = 2.5546-2(1.3155) = -0.0764
$μ+2σ$ = 2.5546+2(1.3155) = 5.1856
Using Chebyshev's theorem, we can state that at least 75% of the number of tires are expected to contain -0.0764 to 5.1856 defective tires on a limo.
Work Step by Step
See above.
