Answer
a. Mean =μ = ∑xP(x) = 1.59
Standard Deviation
= $\sqrt∑x^{2}P(x) -μ^{2}$
= $\sqrt 3.45-1.59^{2}$
=0.9602
b. a. Mean =μ = ∑xP(x) = 7.07
Standard Deviation
= $\sqrt∑x^{2}P(x) -μ^{2}$
= $\sqrt 51.11-7.07^{2}$
=1.0607
Work Step by Step
See above.