Introductory Statistics 9th Edition

Published by Wiley
ISBN 10: 1-11905-571-7
ISBN 13: 978-1-11905-571-6

Chapter 5 - Section 5.3 - Mean and Standard Deviation of a Discrete Random Variable - Exercises - Page 192: 5.16

Answer

a. Mean =μ = ∑xP(x) = 1.59 Standard Deviation = $\sqrt∑x^{2}P(x) -μ^{2}$ = $\sqrt 3.45-1.59^{2}$ =0.9602 b. a. Mean =μ = ∑xP(x) = 7.07 Standard Deviation = $\sqrt∑x^{2}P(x) -μ^{2}$ = $\sqrt 51.11-7.07^{2}$ =1.0607
1562682503

Work Step by Step

See above.
Small 1562682503
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.