Answer
$20C_{6}$= 38760
There are total 38760 combinations possible.
$20P_{6}$= 27907200
There are 27907200 permutations possible.
Work Step by Step
no
Introductory Statistics 9th Edition
by Mann, Prem S.
Published by
Wiley
ISBN 10:
1-11905-571-7
ISBN 13:
978-1-11905-571-6
Chapter 4 - Section 4.6 - Counting Rule, Factorials, Combinations, and Permutations - Exercises - Page 168: 4.91
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