Introductory Statistics 9th Edition

Published by Wiley
ISBN 10: 1-11905-571-7
ISBN 13: 978-1-11905-571-6

Chapter 4 - Section 4.6 - Counting Rule, Factorials, Combinations, and Permutations - Exercises - Page 168: 4.90


$_{12}P_{3}$ = 1320 There are 1320 permutations.

Work Step by Step

All horses are different from one another, therefore the order of selections is important; we find the number of permutations or arrangements using the following formula: $12P_{3}$ = $\frac{12!}{(12-3)!}$ $= \frac{12!}{9!} = 1320$ Thus, there are 1320 permutations or arrangements for selecting 3 horses out of 12 horses.
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