Answer
a. Range = 43, Variance = 169.0208, Standard Deviation = 13.0008
b. Coefficient of Variation = 43.70%
c. The high value of standard deviation indicates that the values in the data set are spread over a larger range around the mean.
Work Step by Step
a. Range = Highest value- Lowest value = 53-10=43
$Variance = σ^2=(∑〖(x-μ)〗^2 )/N $
$=[∑(x^2) -∑(x)^2]/N$
$=[12649-10620.75]/12$
=129.0208
Standard Deviation = $\sqrt 129.0208= 13.0008$
b. Coefficient of Variation = $13.0008\div29.75 \times100% = 43.70%$
