Mean = 429.8 Median = 103.5 No mode 10% Trimmed mean = 124 Trimmed mean is the best way to measure these data.
Work Step by Step
a. Mean = $(45+68+77+82+99+108+127+153+278+3261)\div10 = 429.8$ Median = $(5th + 6th)\div2= (99+108)\div2=103.5$ b.There is no mode in these data sets, because each data occurs only once. c. 10% trimmed mean = 10% of 10 values = 10(0.10) = 1, therefore we drop one value from each end of the ranked data. $(68+77+82+99+108+127+153+278)\div8 = 124$ d. Trimmed mean is suggested because these data contain outliers; trimmed mean can eliminate the outlier and have a better representation of data.