Essentials of Statistics for the Behavioral Sciences 8th Edition

Published by Cengage Learning
ISBN 10: 1133956572
ISBN 13: 978-1-13395-657-0

Chapter 3 - Measures of Central Tendency - Problems - Page 85: 11

Answer

The new mean: $M=15$

Work Step by Step

$M=\frac{∑X}{N}$ There are 6 scores whose mean is $13$: $13=\frac{X_1+X_2+X_3+X_4+X_5+X_6}{6}$ $X_1+X_2+X_3+X_4+X_5+X_6=13\times6=78$ Now, remove a person with a score of $3$. Since the position of this score in the sum above makes no difference, let's name this score as $X_6$ $X_1+X_2+X_3+X_4+X_5+X_6=78$ $X_1+X_2+X_3+X_4+X_5+3=78$ $X_1+X_2+X_3+X_4+X_5=75$ Find the new mean: $M=\frac{∑X}{N}=\frac{X_1+X_2+X_3+X_4+X_5}{5}=\frac{75}{5}=15$
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