Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions - Page 261: 7

Answer

0.9053.

Work Step by Step

$z_1=\frac{value-mean}{standard \ deviation}=\frac{133-100}{15}=2.2.$ $z_2=\frac{value-mean}{standard \ deviation}=\frac{79-100}{15}=-1.4.$ Using the table, the value belonging to 2.2: 0.9861, the table, the value belonging to -1.4: 0.0808. 0.9861-0.0808=0.9053.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions
GradeSaver will pay $500 for your Textbook Answer contributions