## Essentials of Statistics (5th Edition)

Published by Pearson

# Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions - Page 261: 5

0.885

#### Work Step by Step

$z=\frac{value-mean}{standard \ deviation}=\frac{118-100}{15}=1.2.$ Using the table, the value belonging to 1.2: 0.885.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.