Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions: 5

Answer

0.885

Work Step by Step

$z=\frac{value-mean}{standard \ deviation}=\frac{118-100}{15}=1.2.$ Using the table, the value belonging to 1.2: 0.885.
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