Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 4 - Probability - 4-3 Addition Rule - Page 156: 41

Answer

P(A exclusive or B)=P(A)+P(B).

Work Step by Step

By the picture: P(A exclusive or B)$=P(A)+P(B)- 2\cdot P(A \ and \ B).$ But $P(A \ and \ B)$ is 0, hence P(A exclusive or B)=P(A)+P(B).
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