#### Answer

P(A exclusive or B)=P(A)+P(B).

#### Work Step by Step

By the picture: P(A exclusive or B)$=P(A)+P(B)- 2\cdot P(A \ and \ B).$ But $P(A \ and \ B)$ is 0, hence P(A exclusive or B)=P(A)+P(B).

Published by
Pearson

ISBN 10:
0-32192-459-2

ISBN 13:
978-0-32192-459-9

P(A exclusive or B)=P(A)+P(B).

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