Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 4 - Probability - 4-3 Addition Rule - Page 156: 39

Answer

$0.75$

Work Step by Step

We know that $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$ and by the inclusion-exclusion principle:$P(A \cup B)=P(A)+P(B)-P(A\cap B)$. A:getting a baby girl B:if tossing a coin, getting a head. By checking the data: $P(A)=\frac{1}{2}$ $P(B)=\frac{1}{2}$ $P(A\cap B)=\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4}$ Therefore getting a baby girl or if tossing a coin, getting a head: $P(A \cup B)=\frac{1}{2}+\frac{1}{2}-\frac{1}{4}=\frac{3}{4}=0.75$
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