Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation: 15

Answer

Variance:12.3. Standard deviation:3.5 Range:11.

Work Step by Step

By using the results from before: $\mu=6.5.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(4-6.5)^2+(4-6.5)^2+...+(15-6.5)^2}{20}=12.3.$ Standard deviation=$\sqrt{variance}=\sqrt{11.675}=3.5$ Range=maximum value-minimum value=$15-4=11$.
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