Answer
Variance:$5.958 \cdot10^{13} \ (\$)^2$. Standard deviation:$7,719,020 \$$ Range:$19,628,584\$$.
Work Step by Step
The mean can be counted by summing all the data and dividing it by the number of data:$\frac{ 17,688,241+1+19,628,585+12,407,800+14,765,710} {5}=12,898,007.$$\mu=12,898,007 \ \$.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(17,668,241-12,898,007)^2+(1-12,898,007)^2+...+(14,765,410-12,898,007)^2}{5}=5.958 \cdot10^{13} \ (\$)^2.$ Standard deviation=$\sqrt{variance}=\sqrt{5.958 \cdot10^{13} \ (\$)^2}=7,719,020 \$$ Range=maximum value-minimum value=$19,628,585 \$-1 \$=19,628,584\$$.
