Answer
Variance:$10547.95(million \$)^2.$ Standard deviation:$102.7 \ million \$$ Range:265m\$.
Work Step by Step
The average can be counted by summing all the data and dividing it by the number of data: $\frac{332+302+235+225+100+90+88+84+75+67}{10}=159.8.$ $\mu=159.8 \ million.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(332m-159.8m)^2+(302m-159.8m)^2+...+(67m-159.8m)^2}{10}=10547.95 (million \$)^2.$ Standard deviation=$\sqrt{variance}=\sqrt{9493.16(million \$)^2}=102.7 \ million \$$ Range=maximum value-minimum value=332m\$-67m\$=265m\$.
