Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation - Page 107: 10

Answer

Variance:$101.12\ (deaths)^2$. Standard deviation:$10.06 \ deaths$ Range:$28 \ deaths$.

Work Step by Step

The mean can be counted by summing all the data and dividing it by the number of data: $\frac{78+81+95+73+69+79+92+73+90+97}{10}=82.7$: $\mu=82.7 \ deaths.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(78-82.7)^2+(81-82.7)^2+...+(97-82.7)^2}{10}=101.12\ (deaths)^2.$ Standard deviation=$\sqrt{variance}=\sqrt{101.12\ (deaths)^2}=10.06 \ deaths$ Range=maximum value-minimum value=$97 \ deaths-69 \ deaths=28 \ deaths$.
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