Answer
Mean:51596.6, no mode, median: 51193, midrange:52642.5. The only thing that is for sure that the mean of all U.S. colleges must be less than 51596.6.
Work Step by Step
The mean can be counted by summing all the data and dividing it by the number of data: $\frac{54410+51991+51730+51300+51196+51190+51122+51115+51037+50875}{10}=51596.6$, the mean is 51596.6. The mode is the data occuring the most times but here all data occurs one time, therefore there is no mode. The median is the average of the 1 or 2 (here 2) middle data: (51196+51190)/2=51193, the median is 51193. The midrange is the average of the highest and the lowest data: (54410+50875)/2=52642.5, the midrange is 52642.5. The only thing that is for sure that the mean of all U.S. colleges must be less than 51596.6.
