Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 6 - The Normal Distribution - Review Exercises - Section 6-3 - Page 363: 13


a. 0.014 b. 0.964

Work Step by Step

a. The probability that the sample mean confectionary consumption for a random sample of 40 American consumers was greater than 27 pounds Given $\mu1=25.7, \sigma1=3.75, n1=40$, $z(27)=\frac{27-25.7}{3.75/\sqrt {40}}=2.19$ The probability above z=2.19 is 0.014 b. The probability that for a random sample of 50, the sample mean for confectionary spending exceeded 60.00 Given $\mu2=61.50, \sigma2=5.89, n2=50$, $z(60)=\frac{60-61.5}{5.89/\sqrt {50}}=-1.80$ The probability above z=-1.80 is 0.964
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