Chapter 6 - The Normal Distribution - Review Exercises - Section 6-2 - Page 362: 7

a. 0.362 b. 0.119 c. 0.061

Given $\mu=476, \sigma=22$ a. Between 476 and 500 passengers $z(500)=\frac{500-476}{22}=1.091$ The probability between z=0 and 1.091 is 0.362 b. Less than 450 passengers $z(450)=\frac{450-476}{22}=-1.182$ The probability below z=-1.182 is 0.119 c. More than 510 passengers $z(510)=\frac{510-476}{22}=1.545$ The probability above z=1.545 is 0.061